# use the reduce metaoperator [ ] with infix + to do "sum all" [+] 1, 2, 3
say [+] 1..10000000000000000000000000000000000000000000
50000000000000000000000000000000000000000005000000000000000000000000000000000000000000
(It actually cheats because that particular operator gets substituted for `sum` which knows how to calculate the sum of a Range object.)