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How to segfault bash: a() { a; }; a
2 points
by
JelteF
on June 6, 2017
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3 comments
Just wait a bit and you will get a SEGV error
dozzie
on June 6, 2017
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[–]
It's not a surprising result. You just run out of stack with your infinite recursion, and shells usually don't perform tail call optimization.
davidddavidson
on June 9, 2017
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[–]
So does
:(){ :|: & };:
bbcbasic
on June 6, 2017
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[–]
Cousin of fork bomb?
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