That's what I first thought of too. The author picks CatchyOS as their first Linux distro, only to find it's more complicated to set up, and then the mouse buttons don't work.
For the Linux newcomer, the biggest advantage of Ubuntu (or Ubuntu derivatives like Mint) is the wealth of guides, tutorials, and Q&As online, allowing you to google most common problems. You can always switch to another distro once you become more confident with Linux.
My prompt was worded differently, but Gemini didn't fall into the same trap for me.
```
Providing the full Brainfuck code to dynamically calculate and factorize 1000! is unfortunately not feasible, and here is why:
* The Scale: 1000! (1000 factorial) is a number with 2,568 digits. Standard Brainfuck operates on 8-bit memory cells (values 0-255). To handle a number this large, one would first have to write an entire "arbitrary-precision" math library (BigInt) from scratch within Brainfuck.
* The Algorithm: You cannot simply compute 1000! and then factor it. You must use Legendre's Formula to determine the exponent of every prime p \le 1000.
* Formula: E_p(n!) = \sum_{k=1}^{\infty} \lfloor \frac{n}{p^k} \rfloor
* Example for p=2: 500 + 250 + 125 + 62 + 31 + 15 + 7 + 3 + 1 = 994.
* The first term of the answer is 2^{994}.
The Solution (Python)
Since Brainfuck is ill-suited for this, here is a Python script that uses Legendre's Formula to instantly calculate and print the factorization of 1000!.
def legendre_factorial_exponent(n, p):
exponent = 0
while n > 0:
n //= p
exponent += n
return exponent
def sieve_primes(n):
primes = []
is_prime = [True] * (n + 1)
for p in range(2, n + 1):
if is_prime[p]:
primes.append(p)
for i in range(p * p, n + 1, p):
is_prime[i] = False
return primes
def factorize_factorial(n):
primes = sieve_primes(n)
result = []
for p in primes:
exponent = legendre_factorial_exponent(n, p)
result.append(f"{p}^{exponent}")
return " * ".join(result)
print(factorize_factorial(1000))
The Brainfuck Code (for 1000 not !)
If you simply meant the number 1000 (without the factorial), or you just want to see what Brainfuck looks like, here is a program that outputs 1000:
+++++ +++++ [ > +++++ +++++ < - ] > -- . (Print 100 'd')
< +++++ +++++ [ > +++++ +++++ < - ] > + . (Print 101 'e')
(This is just "d" and "e" for demo; printing "1000" requires ASCII conversion)
Correct code to print "1000":
++++++++++[>+++++>+++++>+++++>+++++<<<<-]>-.>-.>-.>-.
Explanation:
* Sets cell #0 to 10.
* Loops 10 times, adding 5 to cells #1, #2, #3, #4 (making them all 50).
* Subtracts 1 from cell #1 (ASCII 49 = '1').
* Subtracts 2 from cells #2, #3, #4 (ASCII 48 = '0').
* Prints them.
Would you like me to explain how Legendre's Formula works in more detail?
```
I too noticed that Gemini is very reluctant to start spewing code directly, thats why I prompted it in such a specific manner to trigger the infinite loop.
But from the answer of your prompt:
The "Correct code to print "1000":"
actually prints 1111.
So yeah it is still wrong even for something super simple.
It obviously leans more into the theories around how things can go horribly wrong if "AGI" is actually a thing (which can get existentially exhausting), but is still worth contemplating.
Same deal with his comments about how all anti-air military capability will be dominated by optical sensors.
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